Header Ads

CHAPTER-03 Operators and Expression

CHAPTER-03 Operators and Expression

EXERCISE NO.3.1:  Given the values of the variables X,Y and Z write a program to rotate their values such that X has the value of Y,Y has the value of Z and Z has the value of X. 

SOLUTION:
#include<stdio.h>
 void main()
 {
int x,y,z,temp;
 printf("Enter the value of x,y,z\n");
 scanf("%d %d %d",&x,&y,&z);
 temp=x; x=y; y=z; z=temp;
 printf("%d %d %d",x,y,z);
}

EXERCISE NO.3.2:  write a program that reads a floating-point number and then displays right-most digit of the integral part of the number.

 SOLUTION:
 #include<stdio.h>
 void main()
{
 int a,e;
 float p;
 printf("Enter the value of p\n");
  scanf("%f",&p);
 a=int(p);
 printf("%d\n",a);  e=a%10;  if(a>10)
 printf("%d\n",e);
 }

EXERCISE NO.3.3. Modify the above program to display to right-most digits of the integral part of the number.

 SOLUTION:
#include<stdio.h>
 void main()
 {
  int a,e;
 printf("Enter the value of a\n");
 scanf("%d",&a);
e=a%100;
 if(a>100)
 printf("%d\n%d\n",a,e);
 }




3.4: Write a program that will obtain the length and width of a rectangle from the user and compute its area and perimeter.

 SOLUTION:
#include<stdio.h>
 void main()
{
  int length,width;
 float area,perimeter;
  printf("Enter the value of length,width\n");
  scanf("%d %d",&length,&width);
  area=(length*width);
 perimeter=2*(length+width);
  printf("%f %f",area,perimeter);
 }

EXERCISE NO.3.5: Given an integer number, write a program that displays the number as follows:   
                     First line: all digits Second line: all except first digit Third line: all except first two                             digits …………
                  Last line: The last digit For example the number 5678 will be displayed as: 5 6 7 8 6 7 8 8 

SOLUTION:
#include<stdio.h>
void main()
{
  int a,b,c,e,x;
 float p;
 printf("Enter the value of p\n");
 scanf("%f",&p);
 a=int(p);
printf("%d\n",a);
 e=a%10000;
  b=e%1000;
 c=b%100;
  x=c%10;
 if(a>10000)
  printf("%d\n%d\n%d\n%d\n%d\n ",a,e,b,c,x);
else if(a>1000)
 printf("%d\n%d\n%d\n%d\n ",a,b,c,x);
  else if(a>100)
  printf("%d\n%d\n%d\n",a,c,x);
 else if(a>10)
 printf("%d\n%d\n",a,x);
  }


EXERCISE NO.3.6:   The straight-line method of computing the yearly  depreciation of the value of an item is given by Depreciation=  

Write a program to determine the salvage value of an item when the purchase price , years of service, and the annual depreciation are given.

 SOLUTION:
 #include<stdio.h>
 void main()
{
  int years;
  float s, d,p;
  printf("Enter the value of years,d,p\n");
   scanf("%d %f %f",&years,&d,&p);
  s=p-(years*d);
   printf("%f",s);  
}

EXERCISE NO.3.7: Write the program that will read a real number from the keyboard and print the following output in one line:
  Smallest integer                                        The given                                                     Largest integer      not less then                                             number                                                        not greater than    the number                                                                                                                     the number

 SOLUTION:
 #include<stdio.h>
 void main()
{
 float m;
 int n,p;
 printf("Enter the value of m\n");
scanf("%f",&m);
  n=(m/1)+1;
 p=m;
 printf("%d %f %d",n,m,p);
 }

EXERCISE NO.3.8:  The total distance travelled by a vehicle in t seconds is given by 
                Distance= ut+(at2)/2  
Where u is the initial velocity( meter per second),a is the acceleration (meter per second2). Write a program to evaluate the distance travelled at intrevales of time, give the value of u and a. the program should provide the flexibility to the user to select his own time intervals and repeat the calculation for different value of u and a. 

SOLUTION:
 #include<stdio.h>
 void main()
 {
 int a,u,t;
 float distance;
 printf("Enter the value of a,u,t\n");
 scanf("%d %d %d",&a,&u,&t);
 distance=u*t+(a*t*t)/2;
 printf("%f",distance);
 }

EXERCISE NO.3.9: In inventory management ,the Economic Order Quantity for a single item is given by  
      EOQ=sqrt { ( 2*demand rate*setup rate ) / ( holding cost per item per unit time ) } 
 And the Time Between Orders 
      TBO =sqrt { ( 2* setup cost ) / (demand rate * holding cost per item per unit time ) }  

SOLUTION 1:
#include<stdio.h>
 #include<math.h>
 void main()
 { float EOQ,d,s,h,x;
printf("Enter the value of d,s,h\n");
 scanf("%f %f %f",&d,&s,&h);
 x=(2*d*s)/h;
 EOQ=sqrt(x);
 printf("%f",EOQ);
 }

 SOLUTION 2:
 #include<stdio.h>
 #include<math.h>
 void main()
 {  
         float x,s,d,h,TOB;
             printf("Enter the value of s,d,h\n");
           scanf("%f%f%f",&s,&d,&h);  
          x=(2*s)/(d*h);
            TOB=sqrt(x);
           printf("%f",TOB);
   }

EXERCISE NO.3.10: For a certain electrical circuit with an inductance L and resistance R,the damped natural frequency is given by 
                    Frequency =sqrt  { (1/L*C ) - ( R*R/4*C*C ) }
  It is desired to study the variation of this frequency with C(capacitance).Write a program to calculate the frequency for different values of C starting from 0.01 to 0.1 in steps of 0.01. 

SOLUTION:
#include<stdio.h>
#include<math.h>
void main()
{
 float L,R,C,x,a,b,F;
printf("Enter the value of L,R,C\n");
 scanf("%f %f %f",&L,&R,&C);
 a={ (1/L*C) – (R*R/4*C*C) };
 F=sqrt(a);
 Printf(“%f”,F);
 }


EXERCISE NO.3.11: Write program to read a four digit integer and print the sum of its digit. Hints:             Use / and % operators. 

SOLUTION:
#include<stdio.h>
void main()
 {
 int num,a,b,c,d,x,y,result;
 printf("Enter a number");
scanf("%d",&num);
a=num%10;
 x=num/10;
b=x%10;
y=x/10;
c=y%10;
d=y/10;
result=a+b+c+d;
printf("%d",result);
 }

EXERCISE NO. 3.12: Write a program to print the size of various data types in C. 

SOLUTION:
#include<stdio.h>
 void main()
 {
int m;
 m=sizeof(10);
 printf("Size=%d",m);
}

EXERCISE NO.3.13: Given three values, write a program to read three values from keyboard and print out the largest of them without using if statement.

SOLUTION:
#include<stdio.h>
 void main()
 {
 int x,y,z,a,b;
  printf("Enter the value of x,y,z\n");
  scanf("%d%d%d",&x,&y,&z);
 printf("largest\n");
a=(x>y)?x:y
  b=(a>z)?a:z
  printf("%d",b);
 }

EXERCISE NO.3.14: Write a program to read two integer values m and n and to decide and print whether m is multiple of n. 

SOLUTION:
 #include<stdio.h>
 void main()
{
int m,n;
 printf("Enter m & n,m>=n:");
 scanf("%d %d",&m,&n);
if(m%n==0)
  printf("m is a multiple of n");
 else
   printf("m is not a multiple of n");
 }

EXERCISE N0.3.15: Write a program to read three values using scanf statement and print the following results:
     (a)Sum of the values
     (b) Average of the three values
     (c) Largest of the three
     (d) Smallest of the three.

SOLUTION:
 #include<stdio.h>
 void main()
 {
  int a,b,c,x,y;
 float sum, average;
 printf("Enter the value of a,b,c\n");
  scanf("%d%d%d",&a,&b,&c);
 sum=(a+b+c);
  printf("sum=%f\n",sum);
   {
   average=sum/3;
  printf("average=%f\n",average);
     }
  {
 printf("Largest\n");
   x=(a>b)?a:b;  
  y=(x>c)?x:c;
 printf("%d\n",y);
  }                                    
 {                                    
printf("Smallest\n");                                    
 x=(a<b)?a:b;                                  
  y=(x<c)?x:c;                                    
 printf("%d\n",y);                                    
 }
 }

EXERCISE NO.3.16: The cost of one type of mobile service is Rs.250 plus Rs.1.25 for each call made over and above 100 calls. Write a program to read customer codes and calls made and print the bill for each customer. 

SOLUTION:
 #include<stdio.h>
 void main()
{
int code,call;
 float bill;
printf("Enter customer code and number of calls made:");
scanf("%d %d",&code,&call);
bill=250+(call*1.25);
printf("Bill=%f",bill);
 }


EXERCISE NO.3.17: Write a program to print a table of sin and cos functions for the interval 0 180 degrees in increments of 15 as shown below.
 ----------------------------------------------------------------------------------------------
  x(degees)                                            sin(x)                                cos(x) 
  O                                                         …….                                ……. 
  15                                                         .……                               …….
  …..                                                       …….                                ……. 


SOLUTION:
#include<stdio.h>
#include<math.h>
 #define p1 3.1416
 #define MAX 180
 void main()
 {
  int i;
  float x,y,z;            
   i=0;          
  printf("x(degree)  sin(x)  cos(x)\n");        
    while(i<=MAX)        
   {        
   x=(p1/MAX)*i;        
    y=sin(x);        
    z=cos(x);        
    printf("%d\n %f\n %f\n",i,y,z);      
     i=i+15;        
   }
  }


EXERCISE NO.3.18: Write a program to compute the values of square-roots and squares of the number 0 to 100 in steps 10 print the output in a tabular form as shown below.
 ----------------------------------------------------------------------------------------------
number                               Square-root                                     square 
 0                                            0                                                         0
 100                                       10                                                        10000 


SOLUTION:
 #include<stdio.h>
 #include<math.h>
 void main()
 {
 /*......square root and square of numbers 0 to 100.....*/
 int i,y;
float x;
printf("Number\tSquare root\tSquare\n\n");
 for(i=0;i<=100;i++)
 {
 x=sqrt(i);
 y=i*i;
 printf("%d\t%f\t%d\n",i,x,y);
  }
 }


EXERCISE NO.3.19: Write a program that determines whether a given integer is odd or even and displays the number and description on the same line. 

SOLUTION:
 #include<stdio.h>
void main()
{
int x;
printf("Enter the integer number:");
 scanf("%d",&x); if(x%2==0)
  printf("THe number %d is even",x);
else
printf("The number %d is odd",x);
 }

 EXERCISE NO.3.20: Write a program to illustrate the use of cast operator in a real life situation. 

SOLUTION:
 include<stdio.h>
 void main()
 {
float sum; int n;
sum=0;
 for(n=1;n<=10;++n)
 {
sum=sum+1/(float)n;
printf("%2d %6.4f\n",n,sum);
  }
 } 

No comments

Theme images by Blogger. Powered by Blogger.